Ilya and Anya each deserve to run in ~ a rate of 8.30mph and also walk in ~ a speed of 3.90mph . They collection off together on a course of size 5.00miles . Anya walks half of the distance and runs the other half, while Ilya walks fifty percent of the time and also runs the various other half.

You are watching: How long does it take anya to cover the distance of 5.00 miles ?

How long does it take Anya come cover the distance of 5.00miles ?

Express your answer numerically, in minutes.

Find Anya"s typical speed.

Express Anya"s average speed save,Anya numerically, in miles per hour.

How lengthy does it take Ilya to cover the distance?

Express the time tIlya take away by Ilya numerically, in minutes.

Now discover Ilya"s median speed.

Express Ilya"s mean speed save,Ilya numerically, in miles per hour.



modify
included Tue, 29 Mar "16

Treebeard
31978
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2

Given , to run speed(RS) = 8.3 mph

Walking rate (WS) = 3.9 mph

Total distance = 5 miles

Time take away by Anya to cover the distance = (2.5/3.9) +(2.5/8.3) hours

= < (2.5/3.9) + (2.5/8.3) > * 60 mins

= 56.53 minutes

Anya"s typical speed = (5/56.53)*60 mph = 5.30 mph

Time taken by Ilya come cover the street =

let time bring away by Ilya come cover the street be t hours.

then Ilya walks for t/2 hours and also runs for t/2 hours

so , RS*t/2 + WS*t/2 = 5 miles

8.3*t/2 + 3.9*t/2 = 5

or t/2*(8.3+3.9) = 5

or t = 0.81 hours

or t= 0.81*60 mins = 49.1 mins

Ilyas median speed = 5/0.81 mph = 6.17 mph



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added Tue, 29 Mar "16

Treebeard
31978
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1

anya runs half of the track

t = d / s

t = 2.5 (Half the complete distance) / 8.5 (speed that running)

This is .294 hrs which is around 1058s...

And because that the go part...

t = d / s

t = 2.5 / 3.9

t = 2307s...

So you then include the two..

2307 + 1058 = 3365s = 56.09 minutes.

Therefore to job-related out the mean speed, that is simply distance / time...

See more: About Jumpstart Kindergarten Reading, Jumpstart Kindergarten Reading

(5 / 56.09)x60 = 5.3 mph

for llya

let it takes t time for she to sheathe the track

so for t/2 time she runs and also for various other t/2 time she walks.

for run

d1 = 8.3 x t/2

for walk

d2 = 3.9 x t/2

so d1+d2 = d = 5 miles

s0 6.1 x t = 5

t = 5/6.1 = 0.819 hours = 49.18 minutes (llya"s time)

for llya"s median speed

5/0.819 = 6.10 mph


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added Tue, 29 Mar "16
Treebeard
31978
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add a Comment
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