The best statement that describes the formation of diamonds is that diamonds form in kimberlites under very pressure. The correct wgc2010.org is D. 


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Two players, Amy and Beth, play the following game with a jar containing 100 pennies. The players take turns -- Amy goes first.

A tray of electronic components contains 15 components, 4 of which are defective. If 4 components are selected, what is the poss

wgc2010.org:

a) 0.0007326

b) 0.03223

c) 0.2418

d) 0.2418

Explanation:

To find different probabilities for the selection of components among eleven good and four defective components, we will use the Combination.

a)

*

*

b)

*

*

c)

*

*

d)

*

*



wgc2010.org:

12 grams of Iodine-13 was present 16 days ago

Explanation:

Given:

Amount of Iodine-131 sample present now = 3g

To Find:

Amount of Iodine-131 sample present before 16 days = ?

Solution:

W know that the half life of Iodine-131 is 8days

Let the amount of sample before 16 days be X

Then

The X amount Iodine-131 sample will decay ito ist half after 8 days

after 8 days

=>

*

=>

*

after next 8 days , i.e., 16 days

=>

*

=>

*

Now we know that after 16 days we have 3 grams of Iodine-131 sample

So,

*
= 3

*

X = 12



A 40-turn coil has a diameter of 11 cm. The coil is placed in a spatially uniform magnetic field of magnitude 0.40 T so that the

wgc2010.org:

(a) emf = 0.507 V

(b) emf = 0.0507 V

(c) emf = 0.00234 V

Explanation:

Given;

number of turns of the coil, N = 40 turns

diameter of the coil, d = 11 cm

radius of the coil, r = 5.5 cm = 0.055 m

magnitude of the magnetic field, B = 0.4 T

The magnitude of the induced emf is calculated as;

*

(a) when the time, t = 0.3 s

*

(b) when the time, t = 3.0 s

*

(c) when the time, t = 65 s

*



If a book is knocked off a desk that is .75 m tall at a rate of 2.0 m/s, how far away from the desk does it fall

wgc2010.org: 0.8 m

Explanation:

In the vertical direction, the speed is zero, u = 0.

Distance covered in the vertical direction, s = 0.75 m.

The book would fall with acceleration due to gravity in the vertical direction, a = g = 9.8 m/s²

From the equation of motion,

s = u t + 0.5 a t²

Substituting the above values, we will find out the time taken for the book to hit the ground.

⇒0.75 m=0+0.5×9.8 m/s²×t²

⇒t = √0.153 = 0.39 s ≈ 0.40 s

Now, the horizontal distance covered,

d = v×t ⇒d= 2.0 m/s × 0.40 s =0.8 m

Hence, the book falls 0.8 m away from the desk.


7 0
7 months ago
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