The ideal statement that defines the development of diamonds is that diamonds type in kimberlites under an extremely pressure. The exactly wgc2010.org is D.

You are watching: Which statement best describes the formation of diamonds?

Two players, Amy and also Beth, beat the adhering to game v a jug containing 100 pennies. The football player take transforms -- Amy walk first.

A tray of electronic components includes 15 components, 4 of which are defective. If 4 components are selected, what is the poss

wgc2010.org:

a) 0.0007326

b) 0.03223

c) 0.2418

d) 0.2418

Explanation:

To find various probabilities for the an option of components among eleven an excellent and 4 defective components, we will use the Combination.

a)

b)

c)

d)

wgc2010.org:

12 grams that Iodine-13 was present 16 days ago

Explanation:

Given:

Amount that Iodine-131 sample current now = 3g

To Find:

Amount the Iodine-131 sample present before 16 days = ?

Solution:

W recognize that the half life the Iodine-131 is 8days

Let the amount of sample prior to 16 days it is in X

Then

The X quantity Iodine-131 sample will decay ito ist fifty percent after 8 days

after 8 days

=>

=>

after following 8 days , i.e., 16 days

=>

=>

Now we understand that after 16 job we have actually 3 grams of Iodine-131 sample

So,

= 3

X = 12

A 40-turn coil has a diameter that 11 cm. The coil is inserted in a spatially uniform magnetic ar of size 0.40 T so the the

wgc2010.org:

(a) emf = 0.507 V

(b) emf = 0.0507 V

(c) emf = 0.00234 V

Explanation:

Given;

number of turns of the coil, N = 40 turns

diameter that the coil, d = 11 cm

radius the the coil, r = 5.5 centimeter = 0.055 m

magnitude of the magnetic field, B = 0.4 T

The size of the induced emf is calculation as;

(a) once the time, t = 0.3 s

(b) once the time, t = 3.0 s

(c) as soon as the time, t = 65 s

If a publication is knocked turn off a desk that is .75 m tall at a price of 2.0 m/s, how much away native the workdesk does it fall

wgc2010.org: 0.8 m

Explanation:

In the vertical direction, the rate is zero, u = 0.

Distance extended in the upright direction, s = 0.75 m.

The book would autumn with acceleration because of gravity in the upright direction, a = g = 9.8 m/s²

From the equation of motion,

s = u t + 0.5 a t²

Substituting the over values, us will discover out the time taken for the publication to struggle the ground.

⇒0.75 m=0+0.5×9.8 m/s²×t²

⇒t = √0.153 = 0.39 s ≈ 0.40 s

Now, the horizontal distance covered,

d = v×t ⇒d= 2.0 m/s × 0.40 s =0.8 m

Hence, the publication falls 0.8 m far from the desk.

7 0
7 months ago
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